SOLUTION: (1-i)^10

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Question 385403: (1-i)^10
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
(1-i)^10
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Put into polar form:
r = sqrt(1 + 1) = sqrt(2)
theta = invtan(-1/1) = (3pi/4)
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(1-i)^10 = [(sqrt(2))^10*cis(10(3pi/4))
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= 32*cis((30/4)pi)
= 32*cis(7.5pi)
= 32*(cos(1.5pi)+isin(1.5pi))
= 32*(0-i)
= -32i
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Cheers,
Stan H.