SOLUTION: I am needing help with the following problem please: Evaluate 2x(squared)(Y+Z) where X=2, Y=3 Z=4 I got 15 but I am second guessing myself and wanted to see if I worked the pr

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Question 38539: I am needing help with the following problem please:
Evaluate 2x(squared)(Y+Z) where X=2, Y=3 Z=4
I got 15 but I am second guessing myself and wanted to see if I worked the problem correctly. Thanks for your help...
Answer by lyra(94) About Me  (Show Source):
You can put this solution on YOUR website!
I am afraid that you are incorrect, how did you get that answer?
Here is how to solve the problem:
Solved by pluggable solver: SUBSTITUTION solver -- compute expression given values
Your Result:


YOUR ANSWER


  • Graphical form: %282x%5E2%29%2A%28y%2Bz%29 simplifies to 56
  • Text form: (2x^2)*(y+z) simplifies to 56
  • Cartoon (animation) form: simplify_cartoon%28+%282x%5E2%29%2A%28y%2Bz%29+%29
    For tutors: simplify_cartoon( (2x^2)*(y+z) )
  • If you have a website, here's a link to this solution.

DETAILED EXPLANATION

Look at highlight_red%28+%28highlight_red%28+2%2Ax%5E2+%29%29%2A%28y%2Bz%29+%29.
Remove unneeded parentheses around factor highlight_red%28+2+%29,highlight_red%28+x%5E2+%29
It becomes highlight_green%28+2+%29%2Ahighlight_green%28+x%5E2+%29%2A%28y%2Bz%29.
Look at 2%2Ahighlight_red%28+x+%29%5E2%2A%28y%2Bz%29.
Replaced x with 2
It becomes 2%2Ahighlight_green%28+2+%29%5E2%2A%28y%2Bz%29.
Look at 2%2Ahighlight_red%28+2+%29%5Ehighlight_red%28+2+%29%2A%28y%2Bz%29.
Replace constants in factor: highlight_red%28+2+%29,highlight_red%28+2+%29 with highlight_green%28+4+%29
It becomes 2%2Ahighlight_green%28+4+%29%2A%28y%2Bz%29.
Look at 2%2A4%2A%28highlight_red%28+y+%29%2Bz%29.
Replaced y with 3
It becomes 2%2A4%2A%28highlight_green%28+3+%29%2Bz%29.
Look at 2%2A4%2A%283%2Bhighlight_red%28+z+%29%29.
Replaced z with 4
It becomes 2%2A4%2A%283%2Bhighlight_green%28+4+%29%29.
Look at 2%2A4%2A%28highlight_red%28+3+%29%2Bhighlight_red%28+4+%29%29.
Added fractions or integers together
It becomes 2%2A4%2A%28highlight_green%28+7+%29%29.
Look at highlight_red%28+2%2A4%2A%28highlight_red%28+7+%29%29+%29.
Remove unneeded parentheses around factor highlight_red%28+7+%29
It becomes 2%2A4%2Ahighlight_green%28+7+%29.
Look at highlight_red%28+2+%29%2Ahighlight_red%28+4+%29%2Ahighlight_red%28+7+%29.
Multiplied numerator integers
It becomes highlight_green%28+56+%29.
Result: 56

Universal Simplifier and Solver


Done!


Hope this helps and feel free to contact me with further questions,
lyra