SOLUTION: Write the slope-intercept equation for the line that passes through (-7, 6) and is perpendicular to -7x + 9y = -2 Please show all of your work. can someone help me with this

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: Write the slope-intercept equation for the line that passes through (-7, 6) and is perpendicular to -7x + 9y = -2 Please show all of your work. can someone help me with this       Log On


   

Question 385134: Write the slope-intercept equation for the line that passes through (-7, 6) and is perpendicular to -7x + 9y = -2 Please show all of your work. can someone help me with this
Found 2 solutions by mananth, armstrkl:
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
Write the slope-intercept equation for the line that passes through (-7, 6) and is perpendicular to -7x + 9y = -2 Please show all of your work. can someone help me with this
...
-7x + 9y = -2
+7x
9y=7x-2
/9
y=(7/9)x-(2/9)
slope = 7/9
..
slope of line perpendicular will be (-9/7)
..
Point (-7,6) slope (-9/7)
find b in y = mx +b
6=(-9/7)*-7+b
6=9+b
b=-9+6
b=-3
...
The equation is
%28highlight%28y=%28-9%2F7%29x-3%29%29
...
m.ananth@hotmail.ca

Answer by armstrkl(28) About Me  (Show Source):
You can put this solution on YOUR website!

First you find the slope of the line you were given, which is found by solving the equation for y and looking at the coefficient of x.
y=7/9x-2
So the slope of this line is m=7/9
The slope of a perpendicular line is the negative reciprocal, so the new m = -9/7.
Use the point slope formula to find the equation of the line that goes through a point with a given slope, y-y1=m(x-x1). Your point is (-7,6) so x1=-7 and y1=6. Plug in and solve the equation for y.
y-6 = -9/7(x- (-7)) plugged in
y-6 = -9/7x -9 distribute -9/7
y = -9/7x -3 add 6 to both sides
so the answer is y = -9/7x - 3 hope that helped!