SOLUTION: find x' for x=(t) defined implactitly by the given equation evaluate x' at the indicated point 1) x^3 - tx^2 - 4 = o;(-3,-2)

Algebra ->  Test -> SOLUTION: find x' for x=(t) defined implactitly by the given equation evaluate x' at the indicated point 1) x^3 - tx^2 - 4 = o;(-3,-2)      Log On


   

Question 384716: find x' for x=(t) defined implactitly by the given equation evaluate x' at the indicated point
1) x^3 - tx^2 - 4 = o;(-3,-2)
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
+x%5E3+-tx%5E2+-+4=+0+
3x%5E2%2Adx-%28t%282x%2Adx%29%2Bx%5E2%2Adt%29=0
3x%5E2%2Adx-2xt%2Adx-x%5E2%2Adt=0
%283x%5E2-2xt%29%2Adx=x%5E2%2Adt
dx%2Fdt=x%5E2%2F%283x%5E2-2xt%29
.
.
If t=-3 and x=-2, then,
dx%2Fdt=4%2F%2812-12%29
dx%2Fdt is undefined.
.
.
.
If t=-2 and x=-3, then,
dx%2Fdt=9%2F%2827-12%29
dx%2Fdt=9%2F15
dx%2Fdt=3%2F5