SOLUTION: Andrew factored expression 14x^3 - 21x^2 - 7x as 7x(14x^2 - 21x - 7) but when Melissa applied the distribution law and multiplied out 7x(14x - 21x - 7), she got 98x^3 - 147x^2 - 49

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Andrew factored expression 14x^3 - 21x^2 - 7x as 7x(14x^2 - 21x - 7) but when Melissa applied the distribution law and multiplied out 7x(14x - 21x - 7), she got 98x^3 - 147x^2 - 49      Log On


   



Question 384689: Andrew factored expression 14x^3 - 21x^2 - 7x as 7x(14x^2 - 21x - 7) but when Melissa applied the distribution law and multiplied out 7x(14x - 21x - 7), she got 98x^3 - 147x^2 - 49x; thus, Andrew's solution does not appear to check. Why is that? Help Andrew understand better. Explain reasoning and correctly factor the original expression if possible. If expression is prime, state this.
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
14x^3 - 21x^2 - 7x
=7x(2x^2-3x-1)