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Question 384637: ***I NEED THE STEPS TO SOLVE THIS PROBLEM SO THAT I CAN BETTER UNDERSTAND IT...PLEASE HELP***
ANSWER: 10,125 WATTS
PROBLEM: POWER OF WIND ROTOR
The power (P) generated by a wind rotor is directly proportional to the product of the square of the area (A) swept out by the blades and the third power of the wind velocity (v). Suppose the diameter of the circular area swept out by the blades is 10ft, and P=3000 watts when v=20mi/hr. Find the power generated when the wind velocity is 30mi/hr.
THANK YOU!!!
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! The power (P) generated by a wind rotor is directly proportional to the product of the square of the area (A) swept out by the blades and the third power of the wind velocity (v).
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P = k*A^2*V^3
Solve for "k using the following.
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Suppose the diameter of the circular area swept out by the blades is 10ft, and P=3000 watts when v=20mi/hr.
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3000 = k*(pi*5^2)^2*20^3
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3000 = k*(6168.5)*8000
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k = 3000/49348000
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k = 0.00006079
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Equation for this windmill:
P = 0.00006079274*A^2*V^3
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Find the power generated when the wind velocity is 30mi/hr.
P = 0.00006079274(pi*5^2)(30)^3
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P = 10125 watts
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Cheers,
Stan H.
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