SOLUTION: I need help dividing the following: 3y+12/8y^3 ÷ 9y+36/16y^3

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Question 384603: I need help dividing the following:
3y+12/8y^3 ÷ 9y+36/16y^3
Found 2 solutions by Alan3354, stanbon:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
%28%283y%2B12%29%2F8y%5E3%29%2F%28%289y%2B36%29%2F16y%5E3%29
Invert the divisor and multiply
%28%283y%2B12%29%2F8y%5E3%29%2A%2816y%5E3%2F%289y%2B36%29%29
Factor, then cancel things.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
I need help dividing the following:
[3y+12/8y^3] ÷ [9y+36/16y^3]
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[3(y+4)/8y^3]
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Cancel all factors common to a numerator and a denominator to get:
[1/1]
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= 2/3
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cheers,
Stan H.