SOLUTION: A chemist has a 45% mixture of hydrochloric acid and 80% mixture of the same acid. How Much of each should be mixed together to get 60ml of a 60% solution of hydrochloric acid??
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Question 384450: A chemist has a 45% mixture of hydrochloric acid and 80% mixture of the same acid. How Much of each should be mixed together to get 60ml of a 60% solution of hydrochloric acid?? Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! let x = the amount (ml) of 45% mixture should be mixed with the 80% solution
then 60-x = the amount (ml) of 80% mixture should be mixed with the 45% solution
mixing these two amounts together will give 60 ml of a 60% solution.
,45x+.8(60-x) =.6(60)
.45x +48-.8x =36
.35x = 12x
x =12/.35 =34.29 ml
60-x =25.71 ml
ans: 34.29 ml of the 45% mixture should be mixed with 25.71 ml of the 80% mixture to get 60 ml of a 60% solution of hydrochloric acid
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