Question 384251: Length of a rectangular room is 8 feet longer than twice the width the room is 184 feet what are the dimensions
Answer by jokaehler(26)   (Show Source):
You can put this solution on YOUR website! I assume that you are looking for perimeter; mark "length" as x and "width" as y.
"The length of a rectangular room is 8 feet longer than twice the width."
(x = 2y + 8)
Perimeter (184) = 2x + 2y
Use the substitution method to solve for y. If x = 2y + 8, then 2(2y + 8) + 2y = 184.
Step 1: 4y + 16 + 2y = 184. (Distributive property)
Step 2: 6y = 168 (Combine like terms)
Step 3: y = 28 (Divide by 6 to isolate y)
Now that you have solved for "y," we can solve for x! If x = 2y + 8, then x = (2*28) + 8.
56 + 8 = x
x = 64
If "x" is length, and "y" is width...
Length: 64
Width: 28
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