SOLUTION: Lucas is 1/3 of a mile away from home, bicycling at 20mph, when his brother takes off on his bike to catch up. How fast must Lucas's brother go to catch him a mile from home?

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: Lucas is 1/3 of a mile away from home, bicycling at 20mph, when his brother takes off on his bike to catch up. How fast must Lucas's brother go to catch him a mile from home?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 384138: Lucas is 1/3 of a mile away from home, bicycling at 20mph, when his brother takes off on his bike to catch up. How fast must Lucas's brother go to catch him a mile from home?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Lucas is 1/3 of a mile away from home, bicycling at 20mph,
when his brother takes off on his bike to catch up.
How fast must Lucas's brother go to catch him a mile from home?
:
We can are phrase this problem to:
Brother will have to travel 1 mile in the same time Lucas travels 2/3 of mile
Let s = brother's speed to accomplish this
:
Write a time equation; Time = dist/speed
1%2Fs = %28%282%2F3%29%29%2F20
Cross multiply
2%2F3s = 20
2s = 3(20)
2s = 60
s = 30 mph would be the brother's speed
:
:
Confirm this find the time of each, should be equal
1/30 = .033 hr
.67/20 = .033 hr