SOLUTION: If a cylinder has a volume of 401.92 inches cubed and a height of 2 in what is the length of the diameter of the base circle to the nearest inch?
Algebra ->
Volume
-> SOLUTION: If a cylinder has a volume of 401.92 inches cubed and a height of 2 in what is the length of the diameter of the base circle to the nearest inch?
Log On
Question 384087: If a cylinder has a volume of 401.92 inches cubed and a height of 2 in what is the length of the diameter of the base circle to the nearest inch? Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! Volume of Cylinder V = pi*r^2*h
h= 2in
V=401.92
..
401.92= pi*r^2*2
divide by 2*pi
401.92/2*pi= r^2
r^2= 63.96
r= 7.99 rounded off to 8 inches
..
diameter = 8*2=16 inches
..
m.ananth@hotmail.ca
