SOLUTION: Hello! I am trying to solve the following:
For the graph of the quadratic function, identify the direction of the opening and the coordinates of the vertex: f(x)= -(x+2)^2-4
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-> SOLUTION: Hello! I am trying to solve the following:
For the graph of the quadratic function, identify the direction of the opening and the coordinates of the vertex: f(x)= -(x+2)^2-4
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Question 383951: Hello! I am trying to solve the following:
For the graph of the quadratic function, identify the direction of the opening and the coordinates of the vertex: f(x)= -(x+2)^2-4
Thanks so much!!
Denise Answer by jokaehler(26) (Show Source):
You can put this solution on YOUR website! This problem can be solved by examining what you are given. You're given -(x+2)^2-4. The problem that you are given is in vertex form. a(x-h)^2+k. a shows direction and intensity of the curve. x is your x value, h is the opposite of the x value for the vertex, and k is your y value for the vertex. What this shows is that the graph opens downward due to the negative value for "a"). The vertex is (-2, -4).
