You can put this solution on YOUR website! let the numbers be x & x+2
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x^2+(x+2)^2=290
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x^2+x^2+4x+4=290
2x^2+4x+4=290
/2
x^2+2x+2-145=0
x^2+2x-143=0
x^2+13x-11x-143=0
x(x+13)-11(x+13)=0
(x+13)(x-11)=0
x=-13 OR 11
So x = -13
The numbers are -13, -11
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