SOLUTION: Diane is 3 times as old as sydney and Josh is 16 years younger than Diane. One year ago, Diane was twice the sum of syndent and Josh age. Find their present ages.
Algebra ->
Customizable Word Problem Solvers
-> Age
-> SOLUTION: Diane is 3 times as old as sydney and Josh is 16 years younger than Diane. One year ago, Diane was twice the sum of syndent and Josh age. Find their present ages.
Log On
Question 383844: Diane is 3 times as old as sydney and Josh is 16 years younger than Diane. One year ago, Diane was twice the sum of syndent and Josh age. Find their present ages. Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! Diane is 3 times as old as sydney and Josh is 16 years younger than Diane. One year ago, Diane was twice the sum of syndent and Josh age. Find their present ages.
..
let Sydney be x years old
Diana = 3x
Josh = 3x-16
..
1 year ago
sydney = x-1
Diana = 3x-1
Josh = 3x-16-1= 3x-17
..
3x-1= 2(x-1+3x-17)
3x-1=2(4x-18)
3x-1= 8x-36
8x-3x=36-1
5x=30
/5
x= 6 ... Sydney's age.
Diana = 18
Josh=38
...
m.ananth@hotmail.ca
