SOLUTION: I am so confused with this. Please help. Graph y=log(base 3)(x+2)+1

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: I am so confused with this. Please help. Graph y=log(base 3)(x+2)+1      Log On


   

Question 383320: I am so confused with this. Please help.
Graph y=log(base 3)(x+2)+1
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Graph y=log3(x+2)+1
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Identify the Domain:
Solve x+2 > 0
x > -2 is the domain
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y = [log3(x+2)] + 1
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Vertical asymptote at x = -2
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x-intercept:
Let y = 0
Then [log3(x+2)] + 1 = 0
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[log3(x+2)] = -1
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x+2 = 3^-1
x+2 = 1/3
x = -5/3
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Plot the asymptote and the point (-5/3,0)
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Sketch the log curve using those two reference facts.
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graph%28400%2C300%2C-10%2C20%2C-10%2C20%2C%28ln%28x%2B2%29%29%2Fln%283%29+%2B+1%29
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Cheers,
Stan H.