SOLUTION: (6xy^2/7y^3)/(15x^2y/5x^2)
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Question 38325
:
(6xy^2/7y^3)/(15x^2y/5x^2)
Answer by
fractalier(6550)
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Okay from
(6xy^2/7y^3)/(15x^2y/5x^2)
Let us invert the second fraction, then we cancel wherever we can in order to simplify...so
(6xy^2/7y^3) * (5x^2/15x^2y) =
(6x / 7y) * (1 / 3y) =
6x / 21y^2 =
2x / 7y^2