Question 382902: log(base4)x-2log3=1
How can I solve Logarithms with different bases? How can I change the bases and make it similar. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! log(base4)x-2log3=1
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log4(x) - log10(9) = 1
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log(x)/log(4) - log(9)/log(10) = 1
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log(x)/log(4) - log(9) = 1
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Multiply thru by log(4) to get:
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log(x) - log(9)*log(4) = log(4)
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log(x) = log(9)*log(4) + log(4)
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log(x) = 1.176571...
x = 10^1.176571
x = 15.016587)
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Cheers,
Stan H.
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