SOLUTION: a bag contains 6 cherry 3 orange and 2 lemon candies you reach in and take 3 pieces of candy at random find the probablity that you have all orange candies. I got 0.7272 not sure i

Algebra ->  Probability-and-statistics -> SOLUTION: a bag contains 6 cherry 3 orange and 2 lemon candies you reach in and take 3 pieces of candy at random find the probablity that you have all orange candies. I got 0.7272 not sure i      Log On


   



Question 382415: a bag contains 6 cherry 3 orange and 2 lemon candies you reach in and take 3 pieces of candy at random find the probablity that you have all orange candies. I got 0.7272 not sure if that is right.
B. find the proability that you have 2 cherry and 1 lemon.
I also got .7272 for this.

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
There are 6+3+2 = 11 candies total

There are 11 C 3 = 165 different ways to select 3 candies (where order doesn't matter)


Since there is only one way to choose 3 orange candies (3 C 3 = 1), this means that the probability is 1%2F165=0.0060606060606 which rounds to 0.006


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Again, there are 11 C 3 = 165 different ways to select 3 candies.


There are 6 C 2 = 15 different ways to select 2 cherry candies and 2 C 1 = 2 different ways to select a single lemon candy.


So there are 15*2 = 30 different ways to select 2 cherries and a lemon.


So the probability is 30%2F165=2%2F11=0.18181818