SOLUTION: Find log (1/2)+log(2/3)+log(3/4)+log(4/5)+log(5/6+log(6/7)....log(98/98)+log(99/100)

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Find log (1/2)+log(2/3)+log(3/4)+log(4/5)+log(5/6+log(6/7)....log(98/98)+log(99/100)      Log On


   

Question 382320: Find log (1/2)+log(2/3)+log(3/4)+log(4/5)+log(5/6+log(6/7)....log(98/98)+log(99/100)
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Find log (1/2)+log(2/3)+log(3/4)+log(4/5)+log(5/6+log(6/7)....log(98/98)+log(99/100)
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Fact: loga(b) = logc(b)/logc(a)
This is the "Change of Base Law".
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Using that over and over and over agin on you problem
you will see that everything cancels except
log(1)/log(100)
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= 0/2 = 0
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Cheers,
Stan H.