SOLUTION: have 34 coins of nickels and dimes where the total value is 1.90.
how many nickels are there?
d + n = 34 n=34-d
.10d + .05n = 1.90
I set the problem up like this...but
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-> SOLUTION: have 34 coins of nickels and dimes where the total value is 1.90.
how many nickels are there?
d + n = 34 n=34-d
.10d + .05n = 1.90
I set the problem up like this...but
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Question 382278: have 34 coins of nickels and dimes where the total value is 1.90.
how many nickels are there?
d + n = 34 n=34-d
.10d + .05n = 1.90
I set the problem up like this...but after several attempts not able to complete this correctly when i try to verify... Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! have 34 coins of nickels and dimes where the total value is 1.90.
how many nickels are there?
d + n = 34 n=34-d
.10d + .05n = 1.90
I set the problem up like this...but after several attempts not able to complete this correctly when i try to verify
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You're doing the right things.
d + n = 34 n=34-d
.10d + .05n = 1.90
Sub for n in the 2nd eqn.
0.1d + 0.05*(34-d) = 1.9
10d + 5(34-d) = 190
5d + 170 = 190
d = 4
n = 30
30 nickels
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There's another approach that might be simpler:
If all 34 coins were nickels, you'd have 170 cents
Each nickel that's replaced by a dime adds 5 to the total.
190 - 170 = 20
20/5 = 4 replacements with dimes
--> 30 nickels
