Question 382274: express as single logarithm: 1/2loga x -5loga x=
Answer by CharlesG2(834)   (Show Source):
You can put this solution on YOUR website! express as single logarithm: 1/2loga x -5loga x=
is "a" in loga the base?, assuming it is
logarithmic rule: nlogb (m) = logb (m^n)
1/2 * loga (x) - 5 * loga (x)
x^(1/2) = sqrt(x)
loga (sqrt(x)) - loga (x^5)
logarithmic rule: logb (m) - logb (n) = logb (m/n)
loga (sqrt(x)/(x^5))
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