SOLUTION: Five friends drove at an average rate of 55 miles per hour to a weekend retreat. On the way home, they took the same route averaged 75 miles per hour. What was the distance between

Algebra ->  Triangles -> SOLUTION: Five friends drove at an average rate of 55 miles per hour to a weekend retreat. On the way home, they took the same route averaged 75 miles per hour. What was the distance between      Log On


   



Question 382212: Five friends drove at an average rate of 55 miles per hour to a weekend retreat. On the way home, they took the same route averaged 75 miles per hour. What was the distance between home and the retreat if the round trip took 10 hours
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Five friends drove at an average rate of 55 miles per hour to a weekend retreat.
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To retreat DATA:
rate = 55 mph ; distance = x miles ; time = x/55 hrs
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On the way home, they took the same route averaged 75 miles per hour.
From the retreat DATA:
rate = 75 mph ; distance = x miles ; time = x/75 hrs
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What was the distance between home and the retreat if the round trip took 10 hours
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Equation:
time + time = 10 hrs.
x/55 + x/75 = 10 hrs.
75x + 55x = 10*55*75
130x = 10*55*75
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130x = 41250
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x = 41250/130
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x = 317.31 miles
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Cheers,
Stan H.
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