SOLUTION: The number of milligrams of a certain radioactive substance present at time (t) is given by A(t)= 774e^-(0.018t). How many milligrams are present at t=75? I hope I gave enough info
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Question 381806: The number of milligrams of a certain radioactive substance present at time (t) is given by A(t)= 774e^-(0.018t). How many milligrams are present at t=75? I hope I gave enough information. Please show each step. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! The number of milligrams of a certain radioactive substance present at time (t) is given by A(t)= 774e^-(0.018t). How many milligrams are present at t=75?
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A(75) = 774e^-(0,018*75) = 774*0.25924 = 200.65 mg
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Cheers,
Stan H.
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