SOLUTION: Find three consecutive odd integers such that five times the middle integer equals 33 more than the sum of the first and the last.

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Question 381611: Find three consecutive odd integers such that five times the middle integer equals 33 more than the sum of the first and the last.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi,         

Let x, (x+2) and (x+4) represent the three consecutive odd integers

Write as we Read***

5(x+2) = x + (x+4) + 33

solving for x

5x + 10 = 2x + 37

   3x = 27

    x = 9

the three consecutive odd integers are 9, 11, 13



CHECKING our Answer***

  45 = 9 + 13 + 33