SOLUTION: When asked to solve x^2 + 4x = 5 by using the quadratic formula, a student did the
following:
x = -4±(√4^2-4·1·5)/2·1 = -4±(√16-20)/2 = -4±(√-4)/2 = -2±i
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Algebra ->
Rational-functions
-> SOLUTION: When asked to solve x^2 + 4x = 5 by using the quadratic formula, a student did the
following:
x = -4±(√4^2-4·1·5)/2·1 = -4±(√16-20)/2 = -4±(√-4)/2 = -2±i
W
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Question 381590: When asked to solve x^2 + 4x = 5 by using the quadratic formula, a student did the
following:
x = -4±(√4^2-4·1·5)/2·1 = -4±(√16-20)/2 = -4±(√-4)/2 = -2±i
What did the student do wrong? Found 2 solutions by Fombitz, rapaljer:Answer by Fombitz(32388) (Show Source):
You can put this solution on YOUR website! Didn't first bring the 5 over to the other side.
She could have then factored instead of using the quadratic formula to get,
with and as solutions.
.
.
.
Instead she used instead of in the quadratic formula and got the wrong answer.
