SOLUTION: Area of rectangle is 95 square feet. Length is 6 feet longer than width, find dimesions of the rectangle. Round each dimension to the nearest tenth.

Algebra ->  Rectangles -> SOLUTION: Area of rectangle is 95 square feet. Length is 6 feet longer than width, find dimesions of the rectangle. Round each dimension to the nearest tenth.      Log On


   

Question 381505: Area of rectangle is 95 square feet. Length is 6 feet longer than width, find dimesions of the rectangle. Round each dimension to the nearest tenth.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi,

Let x and (x + 6) represent the width and length respectively

Area = l*w

  (x + 6)x = 95ft^2

  x^2 + 6x - 95 = 0

 x+=+%28-6+%2B-+sqrt%28+416+%29%29%2F%282%29+

Tossing out the negative solution

  x = 7.2ft, the width to the nearest tenth.  Length 13.2ft   (7.2ft + 6ft)