SOLUTION: FIND FOUR CONSECUTIVE EVEN INTEGERS SO THAT THE SOME OF THE FIRST THREE IS TO MORE THAN THAT TWISE THE FOURTH

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: FIND FOUR CONSECUTIVE EVEN INTEGERS SO THAT THE SOME OF THE FIRST THREE IS TO MORE THAN THAT TWISE THE FOURTH      Log On


   

Question 381474: FIND FOUR CONSECUTIVE EVEN INTEGERS SO THAT THE SOME OF THE FIRST THREE IS TO MORE THAN THAT TWISE THE FOURTH
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

Let x, (x+2), (x+4) and (x+6) represent the FOUR CONSECUTIVE EVEN INTEGERS 

Wrte as we Read

x  + (x+2) + (x+4) = 2(x+6) + 2

solving for x

 3x + 6 = 2x + 12 + 2

  x = 8   8,10,12,14 are FOUR CONSECUTIVE EVEN INTEGERS 

CHECKING our Anwer

 8 + 10 + 12 = 30 = 2*14 + 2