Question 381406: What is the equation of the line that is the perpendicular bisector of the line that passes through (n,5) and (n,-3)?
I've tried putting the numbers in slope formula and got -8/0 but the answer in the back of the book says its wrong. Its suppossed to be in formula like y=n or y=4 but I can't figure out how to get it there. Please help!
Found 2 solutions by jim_thompson5910, Alan3354:
Answer by jim_thompson5910(35256)   (Show Source):
You can put this solution on YOUR website! Hint: Any line that goes through points of the form (n,a) and (n,b) is the equation x = n (basically, the x coordinate is the value n)
Any line that is perpendicular to equations like x = n are of the form y = k, where k is some number. From here, you want a line of the form y = k to go through the midpoint of the line segment with endpoints (n,5) and (n,-3) because this perpendicular line must bisect (ie cut in half) the segment. Let me know if this helps at all.
Answer by Alan3354(69443)  (Show Source):
You can put this solution on YOUR website! What is the equation of the line that is the perpendicular bisector of the line that passes through (n,5) and (n,-3)?
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That is a line parallel to the y-axis.
Lines perpendicular to is are parallel to the x-axis.
The midpoint of (n,5) and (n,-3) is (n,1).
Parallel to the x-axis thru (n,1) -->
y = 1
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