SOLUTION: eight times the sum of three consecutive even integers is 98 more than 23 times the smallest of the three integers. what are the integers?

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Question 381365: eight times the sum of three consecutive even integers is 98 more than 23 times the smallest of the three integers. what are the integers?
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
let the integers be n,n+2,n+4
...
8times the sum
8*(n+n+2+n+4)
8*(3n+6)
...
23 times smallest = 23n
add 98
23n+98
...
8(3n+6)=23n+98
24n+48=23n+98
-23n -23n
24n-23n+48=23n-23n+98
n+48=98
-48 -48
n+48-48=98-48
n=50
...
the numbers are 50, 52,54
..
m.ananth@hotmail.ca