SOLUTION: Suppose one card is selected at random from an ordinary deck of 52 playing cards. Let A= event a queen is selected B= event a diamond is selected Determine P(B/A)

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Question 381230: Suppose one card is selected at random from an ordinary deck of 52 playing cards. Let
A= event a queen is selected
B= event a diamond is selected
Determine P(B/A)
Answer by jim_thompson5910(35256) About Me  (Show Source):
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We're given that event A has occurred, which means that we know that a queen has been selected. There are 4 queens (one of each suit) and only one queen of diamonds. So P(B | A) = 1%2F4


Formally, P(B | A) = P(A intersect B)/P(A), so this means that P(B | A) = P(Queen and diamond)/P(Queen) = (1/52)/(4/52) = 1/4