SOLUTION: Suppose one card is selected at random from an ordinary deck of 52 playing cards. let
A= event a diamond is selected
B= event a club is selected
Determine P(A/(not B))
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-> SOLUTION: Suppose one card is selected at random from an ordinary deck of 52 playing cards. let
A= event a diamond is selected
B= event a club is selected
Determine P(A/(not B))
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Question 381223: Suppose one card is selected at random from an ordinary deck of 52 playing cards. let
A= event a diamond is selected
B= event a club is selected
Determine P(A/(not B)) Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website! Since we're given that event B did NOT happen, this means that there are 52-13 = 39 remaining cards to choose from.
Since there are 13 diamond cards, this means that the probability is