SOLUTION: find the dimensions of a rectangular lot whose perimeter is 40 meters and whose area is 96 square meters.

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Question 380527: find the dimensions of a rectangular lot whose perimeter is 40 meters and whose area is 96 square meters.
Answer by mananth(16946) About Me  (Show Source):
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Perimeter P= 40
2*(l+w)=40
/2
l+w = 20
..
Area = 96
l*w=96
w=96/l
..
plug value of w in
l+w=20
96/l+l=20
(96+l^2)/l=20
96+l^2=20l
l^2-20l+96=0
l^2-12l-8l+96=0
l(l-12)-8(l-12)=0
(l-12)(l-8)=0
l=12 Or 8
..
the dimensions are 12 m by 8 m
...
m.ananth@hotmail.ca