SOLUTION: Find the discriminant and determine the number of real solutions. Then solve.
(I did it but i have a feeling its wrong. Here's the question)
4x^2+9=2x
My work: 4x^2-2x+9=0
Algebra ->
Real-numbers
-> SOLUTION: Find the discriminant and determine the number of real solutions. Then solve.
(I did it but i have a feeling its wrong. Here's the question)
4x^2+9=2x
My work: 4x^2-2x+9=0
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Question 380420: Find the discriminant and determine the number of real solutions. Then solve.
(I did it but i have a feeling its wrong. Here's the question)
4x^2+9=2x
My work: 4x^2-2x+9=0
a=4, b=-2, c=9
Discriminant Formula: b^2-4ac
(-2)^2-4(4)(9)
4-144=-140
-140<0
THE EQUATION THEREFORE HAS 0 REAL SOLUTIONS
Quadratic formula: x=-b±squareroot of b^2-4ac/2a
x=-(-2)± squareroot of (-2)^2-4(4)(9)/2(4)
x=2± squareroot of 4-144/8
x=2± squareroot of -140/8
x=-2/8±i squareroot of 140/8
Simplifies as: x=1/4±i squaretoot of 35/2