Question 380397: I have 30 coins, all nickels, dimes, and quarters, worth $4.60. There are two more dimes than quarters. How many of each kind of coin do I have.
Answer by mananth(16946)   (Show Source):
You can put this solution on YOUR website! I have 30 coins, all nickels, dimes, and quarters, worth $4.60. There are two more dimes than quarters. How many of each kind of coin do I have.
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let quarters be x
dimes = x+2
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dimes + quarters = x+x+2=2x+2
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nickels = 30-(2x+2)
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5(30-(2x+2))+10(x+2)+25x=460
5(30-2x-2)+10x+20+25x=460
150-10x-10+10x+20+25x=460
160+25x=460
-160
25x=460-160
25x=300
/25
x=300/25
x=12 ---- quarters
x+2= 12+2=14 dimes
30-(2x+2)=4 nickels
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check
4*5+14*10+12*25=20+140+300=460
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m.ananth@hotmail.ca
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