SOLUTION: Write the slope-intercept form of an equation for a line that passes through (-1, 0) and is perpendicular to the graph of 3x – 5y = 20.

Hi,

Line perpendicular to the graph of 

3x – 5y = 20  Solving for y to put into the slope-intercept form

3x - 20 = 5y

(2/5)x - 4 = y

Note: the standard slope-intercept form for an equation of a line is y = mx + b  

where m is the slope and b the y-intercept.  

y = (2/5)x - 4 slope of this line is (2/5), line perpendicular to it m = -(5/2}

New line:

 y  = (-5/2)x + b  using ordered pair Pt(-1,0) to solve for b

 0  = -5/2(-1) + b

 -5/2 = b

y = (-5/2)x - 5/2