| 
 
 
| Question 38023:  the polynomial function f(x)=x^3+x^2-5x-6 has a zero at x=-2.that implies that x+2 must be a factor of the polynomial. find the other factors by either polynomial long division, or synthetic division...i really dont mind which process you choose, i just need help grasping these concepts. id say im more familiar with polynomial long division. this is part of a take home extra credit assignment i was given, so i dont have any book info, thank you so much!
 Answer by stanbon(75887)
      (Show Source): 
You can put this solution on YOUR website! f(x)=x^3+x^2-5x-6 has a zero at x=-2 Use your long division.
 Divide f(x) by x+2 and you will get a
 quotient of x^2-x-3 and with a remainder
 of zero.
 Now solve the quotient for x by using the
 quadratic formula, as follows:
 x=[1+sqrt(1+12)]/2=[1+-sqrt(13)]/2
 This means the other two factors are:
 (x-[(1/2)+(1/2)sqrt13]) and (x-[(1/2)-(1/2)sqrt13])
 Cheers,
 Stan H.
 | 
  
 | 
 |