SOLUTION: Evaluate {{{ln(1/3sqrt(e))}}} the 3 is supposed to be over the check, where the invisible 2 usually goes. I got ln 1/e^1/3 whcich then equals -1/3, but I think I'm missing a step.

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Evaluate {{{ln(1/3sqrt(e))}}} the 3 is supposed to be over the check, where the invisible 2 usually goes. I got ln 1/e^1/3 whcich then equals -1/3, but I think I'm missing a step.      Log On


   

Question 38014: Evaluate ln%281%2F3sqrt%28e%29%29 the 3 is supposed to be over the check, where the invisible 2 usually goes. I got ln 1/e^1/3 whcich then equals -1/3, but I think I'm missing a step.
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Your answer is correct: You can write the problem as:
ln%28e%29%5E%28-1%2F3%29+=+%28-1%2F3%29ln%28e%29 But ln%28e%29+=+1, so:
ln%28e%29%5E%28-1%2F3%29+=+-1%2F3