SOLUTION: solve for x 4^x+1=8^2x+3
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Question 380071
:
solve for x
4^x+1=8^2x+3
Answer by
stanbon(75887)
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solve for x
4^(x+1)=8^(2x+3)
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Change to the same base of both sides:
2^(2x+2) = 2^(6x+9)
----
2x+2 = 6x+9
4x = -7
x = -7/4
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Cheers,
Stan H.
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