SOLUTION: I have been working on this problem over 2 hours and can't figure out how to solve it. can you please help?? Any suggestions how to even start?? Thank you.
A population of
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-> SOLUTION: I have been working on this problem over 2 hours and can't figure out how to solve it. can you please help?? Any suggestions how to even start?? Thank you.
A population of
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Question 379901: I have been working on this problem over 2 hours and can't figure out how to solve it. can you please help?? Any suggestions how to even start?? Thank you.
A population of wild rabbits in a local reserve has a cyclic pattern over a year's time; its formula is given by P(t)= 20 cos((pi/6)t)+120, where P represents the number of wild rabbits t months after January (t=0).
a) What is the lowest population possible for the rabbits and when does it occur?
b) When does the population first reach 130 rabbits? When t=?
c) Hunting permits for the rabbits are stopped when the population drops to 100 rabbits. When should the permits be stopped? Answer by kingme18(98) (Show Source):
You can put this solution on YOUR website! a) If you remember what a normal cosine graph looks like, its range has a maximum at 1 and a minimum at -1. This one has an amplitude of 20, so it would have a max of 20 and a min of -20, except that it has been moved up 120. Thus, it vacillates between 100 and 140, making the minimum 100.
To find out when this happens, plug in 100 for P(t). <--see what I meant? Once we get rid of the shifts and amplitude changes, we're back to -1 as the minimum!
In 6 months, it will hit its minimum: 100.
This also answers part c.
b)
In 2 months, the population will reach 130.
