SOLUTION: F(x)=10x^2+40x+42 identify the y intercept and the axis of symmetry

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Question 379796: F(x)=10x^2+40x+42 identify the y intercept and the axis of symmetry
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
When x=0, y=42
(0,42)
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Complete the square to convert the equation to vertex form, y=a%28x-h%29%5E2%2Bk in order to deterine the axis of symmetry.
f%28x%29=10x%5E2%2B40x%2B42
f%28x%29=10%28x%5E2%2B4x%29%2B42
f%28x%29=10%28x%5E2%2B4x%2B4%29%2B42-10%284%29
f%28x%29=10%28x%2B2%29%5E2%2B2
The vertex is (-2,2) and the vertex lies on the axis of symmetry x=-2.
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