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Question 379778: Given: x^2 - y^2 = 8x -2y -13. Find the center, the vertices, the foci, and the asymptotes. Then draw the graph neatly, please.
Answer by Edwin McCravy(20064) (Show Source):
You can put this solution on YOUR website! Given: . Find the center, the vertices, the foci, and the asymptotes. Then draw the graph neatly, please
This is a hyperbola because the and the term have opposite
signs.
Get it like this:
Put parentheses around the first two terms:
Factor -1 out of the last two terms on the left
Take half of -8, get -4, square it get +16, add +16 inside the
first parentheses and add +16 to the right side:
Take half of -2, get -1, square it get +1, add +1 inside the second
parentheses, but because of the - in front of the second parentheses
on the left we add -1 to the right side:
Factor the two parentheses as perfect squares, Combine the terms on the
right.
Get a 1 on the right side by dividing every term through by 2
Compare that to
and since the term in x is the positive one, we know the hyperbola
opens right and left. (As we know the x-axis goes right and left, a
way to remember it).
Comparing further, center = (h,k) = (4,1)
We plot the center
Comparing further:
so
Length of semi-transverse axis = a =
So we draw the transverse axis about 1.4 units
to the right and to the left of the center:
The ends of the transverse axis are the vertices. We subtract "a"
from "h" to get the x-coordinate of the left vertex, so the left
vertex is
(4- ,1).
We add "a" to "h" to get the x-coordinate of the right vertex, so
the right vertex is V(4+ ,1). They have the same
y-coordinate as the center.
so
Length of semi-conjugate axis = b =
So we draw the conjugate axis about 1.4 units
above and below the center:
Next we draw the defining rectangle around the two axes:
We draw the asymptotes by drawing the extended diagonals of the
defining rectangle:
These asymptotes have slopes
The go through the center (4,1) so their equations are gotten using
the point-slope formula:
Finding the equation of the asymptote with the positive slope
Finding the equation of the asymptote with the begative slope
Finally we sketch in the hyperbola:
Edwin
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