SOLUTION: Plz help! 1. what is x if 3x^2-2+7=0 then (x- 1/3)^2= ? 2. If y=b^x and b>1, which one is true: A log y b=x. B. log b x=y. C. another answer(explain)

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Plz help! 1. what is x if 3x^2-2+7=0 then (x- 1/3)^2= ? 2. If y=b^x and b>1, which one is true: A log y b=x. B. log b x=y. C. another answer(explain)      Log On


   

Question 379536: Plz help!
1. what is x if 3x^2-2+7=0 then (x- 1/3)^2= ?
2. If y=b^x and b>1, which one is true: A log y b=x. B. log b x=y. C. another answer(explain)
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi,

1)Assuming the x was ommitted after the -2 

3x^2-2x+7=0  what is being done here..is that the square has been completed:

3(x^2 - 2/3x + 1/9  -1/9) + 7 = 0

3(x^2 - 2/3x + 1/9)+ 3*(-1/9) + 7 = 0

3(x-1/3)^2 - 1/3 + 7 = 0

3(x-1/3)^2  = -20/3

(x-1/3)^2  = -20/9



2)  

    y=b^x and b>1

 

Answer would be other according to the properties of logarithms