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Question 379329: {(x, y): (absolute value sign)x (absolute value sign) + ( abs value) y (abs value) = 1} what is the domain of this relation and is it a function?
Found 2 solutions by robertb, stanbon:
Answer by robertb(5830)   (Show Source):
You can put this solution on YOUR website! The domain of |x| + |y| = 1 is the interval [-1,1]. It is not a function, because, suppose x = -0.5. Then 0.5 + |y| = 1, or |y| = 0.5, or y = 0.5, -0.5 (two values).
Answer by stanbon(75887)  (Show Source):
You can put this solution on YOUR website! {(x, y): (absolute value sign)x (absolute value sign) + ( abs value) y (abs value) = 1} what is the domain of this relation and is it a function?
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|x|+|y| = 1
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Domain?
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|x| = 1-|y|
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|y| is always >= 0
So |x| <= 1
So -1 <= x <=1 is the domain.
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Range?
The same arguments as above apply to |y|
So -1 <= y <= 1 is the range
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cheers,
Stan H.
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