SOLUTION: solve.
the cost of admission to the spring carnival was $50 for a group of 9 children and 2 adults. the admission was $61 for another group of 10 children and 3 adults. what was
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the cost of admission to the spring carnival was $50 for a group of 9 children and 2 adults. the admission was $61 for another group of 10 children and 3 adults. what was
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Question 379084: solve.
the cost of admission to the spring carnival was $50 for a group of 9 children and 2 adults. the admission was $61 for another group of 10 children and 3 adults. what was the admission price for each child? what was the admission price for each adult?
this is what i have so far, im stuck.
children=c adults=a
$50=9c+2a
$61=10c+3a Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! the cost of admission to the spring carnival was $50 for a group of 9 children and 2 adults.
the admission was $61 for another group of 10 children and 3 adults.
what was the admission price for each child?
what was the admission price for each adult?
:
I would write it like this (but your way is OK too)
9c + 2a = 50
10c + 3a = 61
:
To use elimination, multiply the 1st equation by 3, the 2nd equation by 2:
27c + 6a = 150
20c + 6a = 122
----------------Subtraction eliminates a, find c
7c = 28
c =
c = $4 for children
:
Use the 1st original equation to find a, replace c with 4
9c + 2a = 50
9(4) + 2a = 50
36 + 2a = 50
2a = 50 - 36
2a = 14
a =
a = $7 for adults
:
:
We can check these solutions in the 2nd original equation
10c + 3a = 61
10(4) + 3(7) = 61
40 + 21 = 61, confirms our solution
:
How about this, did it make sense to you now?
