SOLUTION: Sally can paint a room in 3 hours while it takes Steve 8 hours to paint the same room. How long would it take them to paint the room if they worked together?
Algebra ->
Rate-of-work-word-problems
-> SOLUTION: Sally can paint a room in 3 hours while it takes Steve 8 hours to paint the same room. How long would it take them to paint the room if they worked together?
Log On
Question 379032: Sally can paint a room in 3 hours while it takes Steve 8 hours to paint the same room. How long would it take them to paint the room if they worked together? Found 3 solutions by ewatrrr, richard1234, stanbon:Answer by ewatrrr(24785) (Show Source):
Hi,
Sally can paint a room in 3 hours while it takes Steve 8 hours
Let x represent the time it takes together. Per hour the Equalizer
1/3hr + 1/8hr = 1/x Multiplying each term by 24x so as all denominators = 1
8x + 3x = 24
11x = 24
x = 2.18 hrs, the time it takes them together
You can put this solution on YOUR website! In one hour, Sally can paint 1/3 of a room and Steve can paint 1/8 of a room. Together, they paint 1/3 + 1/8 = 11/24 of the room in one hour. Therefore, it would take 24/11 hours (approx. 2.18 hours) to paint the entire room.
You can put this solution on YOUR website! Sally can paint a room in 3 hours while it takes Steve 8 hours to paint the same room. How long would it take them to paint the room if they worked together?
-----------------
Sally rate = 1/3 job/hr
Steve rate = 1/8 job/hr
Together rate = 1/x job/hr
---------------------------------
Equation:
rate + rate = together rate
1/3 + 1/8 = 1/x
8x + 3x = 24
11x = 24
x = 24/11 = 2 2/11 hrs
---
together time = 2 hr + (2/11)*60 min = 2 hr 10.9 min
==========================
Cheers,
Stan H.
=================