SOLUTION: perform the indicated operation 6z^2-z-2/12z^2+5z-2 divide sign 4z^2-1/8z^2-6z+1 thanks

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: perform the indicated operation 6z^2-z-2/12z^2+5z-2 divide sign 4z^2-1/8z^2-6z+1 thanks      Log On


   



Question 378832: perform the indicated operation
6z^2-z-2/12z^2+5z-2 divide sign 4z^2-1/8z^2-6z+1
thanks

Found 2 solutions by jsmallt9, mananth:
Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
(Note: Please put multiple term numerators and denominators in parentheses. It makes the problem clearer and tutor are more likely to help when the problem is clear.)

%28%286z%5E2-z-2%29%2F%2812z%5E2%2B5z-2%29%29%2F%28%284z%5E2-1%29%2F%288z%5E2-6z%2B1%29%29
As you learned long ago, when dividing fractions you invert the divisor and change it to multiplication. This is still true even when the fractions look like these.
%28%286z%5E2-z-2%29%2F%2812z%5E2%2B5z-2%29%29%2A%28%288z%5E2-6z%2B1%29%2F%284z%5E2-1%29%29
And when you learned how to multiply fractions you should have also learned that canceling common factors before you multiply made things easier. This is still true. The main difference between now and then is that now the factors are harder to find. Factoring each numerator and denominator we get:

We can now see the factors to cancel:

leaving
%28%28z-1%29%2F1%29%2A%281%2F%282z%2B1%29%29
This is very simple to multiply:
%28z-1%29%2F%282z%2B1%29

P.S. In response to the question in your "Thank you":
"So can you tell me is my answer 1?"
I do not understand the question. The answer is %28z-1%29%2F%282z%2B1%29 which cannot be simplified any further (because there are no common factors to cancel).

Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
%28%286z%5E2-z-2%29%2F%2812z%5E2%2B5z-2%29%29%2F%28%284z%5E2-1%29%2F%288z%5E2-6z%2B1%29%29
...
%28%286z%5E2-z-2%29%2F%2812z%5E2%2B5z-2%29%29%2A%28%288z%5E2-6z%2B1%29%2F%284z%5E2-1%29%29
...

...
%283z-2%29%2F%283z%2B2%29
...
m.ananth@hotmail.ca