SOLUTION: Please help me this problem. Thank you so much. Here is 23^(x) = 10^(-3x)

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Please help me this problem. Thank you so much. Here is 23^(x) = 10^(-3x)      Log On


   

Question 378703: Please help me this problem. Thank you so much. Here is 23^(x) = 10^(-3x)
Found 2 solutions by Alan3354, jim_thompson5910:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
23^(x) = 10^(-3x)
x*log(23) = -3x
x*log(23) + 3x = 0
x*(log(23) + 3) = 0
x = 0

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
23%5E%28x%29=10%5E%28-3x%29 Start with the given equation.


ln%2823%5E%28x%29%29=ln%2810%5E%28-3x%29%29 Take the natural log of both sides.


x%2Aln%2823%29=-3x%2Aln%2810%29 Pull down the exponents.



x%2Aln%2823%29%2B3x%2Aln%2810%29=0 Add 3x%2Aln%2810%29 to both sides.


x%28ln%2823%29%2B3%2Aln%2810%29%29=0 Factor out the GCF 'x' from the left side.


x=0%2F%28ln%2823%29%2B3%2Aln%2810%29%29 Divide both sides by ln%2823%29%2B3x%2Aln%2810%29 to isolate 'x'.


x=0 Divide.


So the solution is x=0


If you need more help, email me at jim_thompson5910@hotmail.com

Also, feel free to check out my tutoring website

Jim