SOLUTION: I'm having a really hard time remembering how to solve this type of question: sin(theta) = 6/7 theta is between 90 and 180 degrees. Find the remaining trig functions. I c

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Question 378695: I'm having a really hard time remembering how to solve this type of question:
sin(theta) = 6/7
theta is between 90 and 180 degrees.
Find the remaining trig functions.
I can get cosine, but after that, I'm lost.

Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
From sin(theta) = 6/7, we take the inverse sine (call it arcsin) of both sides and get
theta = arcsin (6/7)
Be careful that the angle theta is a second quadrant angle...180 - theta gives it to you...
Once you know cos(theta), which you said you already have, finding the rest is like this...
tan x = sin x / cos x
cot x = cos x / sin x
csc x = 1 / sin x
sec x = 1 /cos x