|
Question 378578: Find three consecutive odd intergers such that the sum of the smallest and 4 times the largest is 61.
Answer by ahsomsid(1)   (Show Source):
You can put this solution on YOUR website! Let the smallest integer be an odd number x.
The answer should be x, x+2, x+4 (for example, if x is 7, the three consecutive odd integers would be 7, 9, 11)
The smallest integer is x, and the largest integer is x+4.
The question said the sum of the smallest and 4 times the largest is 61.
So the equation would be: x + 4*(x+4) = 61.
From this point, you just solve the equation.
Distribute the 4 in front of the parenthesis
x + 4x + 16 = 61
combine the x
5x + 16 = 61
subtract 16 from both sides of the equation
5x = 45
divide both sides by 5
x = 9
So the smallest integer is 9, and the other two consecutive odd integers are 11 and 13.
The answer is 9, 11, 13.
|
|
|
| |
