SOLUTION: i have to find the quadratic function {{{y=ax^2+bx+c}}} whose graph passes through the following given points: (-2,7)(1,-2)(2,3). I am REALLY no

Algebra ->  Linear-equations -> SOLUTION: i have to find the quadratic function {{{y=ax^2+bx+c}}} whose graph passes through the following given points: (-2,7)(1,-2)(2,3). I am REALLY no      Log On


   

Question 378510:
i have to find the quadratic function y=ax%5E2%2Bbx%2Bc whose graph passes through the following given points: (-2,7)(1,-2)(2,3). I am REALLY not at all sure about this! I know my "x" in the quad eq. corresponds to the x-coordinate, and the "y" likewise, but how is this denoted, and how do you get just one quad eq. from a system of three? Please help! I'm not even sure where to begin! Thx!






Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
plugging the points into the general equation will give you a system of three equations in a, b, and c
just solve the system for the three values

7 = a(-2)^2 + b(-2) + c ___ 7 = 4a - 2b + c

-2 = a(1)^2 + b(1) + c ___ -2 = a + b + c

3 = a(3)^2 + b(3) + c ___ 3 = 9a + 3b + c